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-   -   Fashionistas you have arrived 3-25-03 - 10-3-03 (http://www.lawtalkers.com/forums/showthread.php?t=8)

Hank Chinaski 09-28-2003 11:01 AM

post-bilmore physics
 
Quote:

Originally posted by Atticus Grinch
I hate to dignify this discussion with my own contribution, but that "slight shift" is, dare I say, illusory.

When Bilmore lifts Bilmore's opponent off the mat in the first place in preparation for the coup de grace, Bilmore would essentially push the Earth down and out of its orbit slightly in order to purchase the requisite potential energy to reside in Bilmore's opponent. At the moment Bilmore releases Bilmore's opponent into brief gravitational free fall, the Earth would be infinitesimally attracted by the mass of Bilmore's opponent (and vice versa, only less infinitesimally for Bilmore's opponent vis-a-vis the Earth, if you catch my drift, har har), and Bilmore's opponent and the mat would necessarily meet in the exact middle, cancelling action and reaction.

In short, the "slight shift of the earth" Bilmore's expecting is only in relation to where the Earth would be if Bilmore's opponent and the Earth could sustain permanent gravitational free fall toward each other. From a distant observer's frame of reference, Bilmore's opponent and the Earth would return to precisely the points in orbit that they were in when the whole enterprise started, accounting for the constant rotation and revolution of the Earth in the meantime.
Ah! The simplicity of a world without entropy. The flaw in your analysis, your Waterloo here as it were, is your attempt to oversimply the problem to eliminate unknown variables. Here, you seem to assume Billmore and opponent as points of force application. Of course, Billmore would be applying these forces through his shoes, and the frictional losses here would vary dependant on his shoe selection that day. If this Paigow woman is correct, and Billmore is wearing white buck loafers, there would be a good deal of sliding. Also, the plaid polyester suit would restrict much of the presumed lifting, creating only more frictional losses. Much of the potential force reactions against the earth would instead manifest themselves in so much raising of dust, and wearing thin of the underarm areas in an otherwise still good jacket.

baltassoc 09-28-2003 01:32 PM

Geek Love
 
Quote:

Originally posted by Atticus Grinch
Not to mention the fact that he spelled it "Weeblo."

Edited to add: Apologies to diva if this was a whiff of her post. I'm still not sure.
Blow me, Timmy.

Oh, wait. Now I see. Heh.

Say_hello_for_me 09-28-2003 02:00 PM

post-bilmore physics
 
Quote:

Originally posted by Hank Chinaski
Ah! The simplicity of a world without entropy. The flaw in your analysis, your Waterloo here as it were, is your attempt to oversimply the problem to eliminate unknown variables. Here, you seem to assume Billmore and opponent as points of force application.
Even Google wouldn't help him here unless he had 100+ hours to understand the additional forces. you start with two masses (Bilmore and his opponent) that independently exert gravitational (static?) forces at t=0, the force being dependent upon the relative location of the center of each mass and the mass itself.

Bilmore lifting his opponent allows the earth's materials, that formerly were deformed by the pressure applied by Bilmore's opponent, to undeform* in a sense. But Bilmore suddenly is applying some measure of the opponent's weight underneath his own (Bilmore's) feet when he lifts his opponent from the earth, causing (additional) deformation under Bilmore's own feet.

Furthermore, Bilmore's exertion of energy to lift his opponent, and presumably moving his opponent's center of mass farther away from the earth's center of mass, alters the earth's position relative to everything else, by changing the gravitational pull. Of course, that requires an understanding that we exert as much gravitational pull on the earth as it does on us at any one time.

It should be noted that energy has been "converted" in a sense by Bilmore's effort. He uses a few of his calories to lift something and next thing you know, the earth is off-kilter.

Furthermore, I note that the gravitational variations are almost insignificant. However, the relative deformations and undeformations, may be significant, depending on the earth's supporting material, Bilmore's mass, and Bilmore's opponent's mass.

And that is without even touching on the external frictional forces from movement.

That is all.

Hello

* If "undeform" is actually a word.

evenodds 09-28-2003 02:55 PM

Yawn and Yea!
 
Physics?
Programming language inventors?

What in the hell is wrong with you people?!!!!!!!!

On a happier and more FB-related note, Roberto Heras has won the Vuelta a Espana after taking back a 1:55 on the penultimate stage -- a mountain time trial.

The Posties become the second team in twenty years to win two grand tours in the same year with two different captains.

Penske, name the other team and captains for extra points.

Say_hello_for_me 09-28-2003 03:17 PM

Yawn and Yea!
 
Quote:

Originally posted by evenodds
Physics?
Programming language inventors?

What in the hell is wrong with you people?!!!!!!!!

Ahh, the innocence of youth. Soon you'll know the wrath of the gravitational Gods and the demons of deformation stress. Be warned of the pull of the earth, for it has always affected your ability to be fashionable in ways that plastic surgery and hip-replacement procedures can't completely fix.

Be warned, ye of little faith. Be warned.

Hello

Anne Elk 09-28-2003 03:17 PM

Geek Love
 
Quote:

Originally posted by tmdiva
[Great book, btw. Anyone else read it?]

It's Webelos, not Weeblos. Silly people.

Not that I agree with the current policies of the BSA, homophobic bastards.

tm
Loved the book. Anything ever happen with the movie? Last I heard Harry Anderson was working on it, but that was years ago.

Greedy,Greedy,Greedy 09-28-2003 03:19 PM

post-bilmore physics
 
Quote:

Originally posted by Say_hello_for_me
Even Google wouldn't help him here unless he had 100+ hours to understand the additional forces. you start with two masses (Bilmore and his opponent) that independently exert gravitational (static?) forces at t=0, the force being dependent upon the relative location of the center of each mass and the mass itself.

Bilmore lifting his opponent allows the earth's materials, that formerly were deformed by the pressure applied by Bilmore's opponent, to undeform* in a sense. But Bilmore suddenly is applying some measure of the opponent's weight underneath his own (Bilmore's) feet when he lifts his opponent from the earth, causing (additional) deformation under Bilmore's own feet.

Furthermore, Bilmore's exertion of energy to lift his opponent, and presumably moving his opponent's center of mass farther away from the earth's center of mass, alters the earth's position relative to everything else, by changing the gravitational pull. Of course, that requires an understanding that we exert as much gravitational pull on the earth as it does on us at any one time.

It should be noted that energy has been "converted" in a sense by Bilmore's effort. He uses a few of his calories to lift something and next thing you know, the earth is off-kilter.

Furthermore, I note that the gravitational variations are almost insignificant. However, the relative deformations and undeformations, may be significant, depending on the earth's supporting material, Bilmore's mass, and Bilmore's opponent's mass.

And that is without even touching on the external frictional forces from movement.

That is all.

Hello

* If "undeform" is actually a word.
I'm not sure I understand this. Can you lay it out in a formula?

Greedy,Greedy,Greedy 09-28-2003 03:32 PM

Quote:

Originally posted by leagleaze
2. You had better not be calling me a patent lawyer.

I think P.C. footnoted you as an example of a geek who is not a patent lawyer. I belive your Ahnuld example withstood P.C.'s scrutiny better than all other Bilmore/Mat/Tree examples.

pretermitted_child 09-28-2003 03:37 PM

Yawn and Yea!
 
Quote:

Originally posted by evenodds
Physics?
Programming language inventors?

What in the hell is wrong with you people?!!!!!!!!

I knew we shouldn't have strayed from the telemarketer discussion.

bilmore 09-28-2003 03:46 PM

post-bilmore physics
 
Quote:

Originally posted by Say_hello_for_me
Even Google wouldn't help him here unless he had 100+ hours to understand the additional forces. you start with two masses (Bilmore and his opponent) that independently exert gravitational (static?) forces at t=0, the force being dependent upon the relative location of the center of each mass and the mass itself.
I think that you all forget that force can be dissipated through heat. You skip the whole subject of the generation of hot air.

Oh, no, wait, you all got that part . . .

;)

pretermitted_child 09-28-2003 03:52 PM

Quote:

Originally posted by Greedy,Greedy,Greedy
I belive [sic] your Ahnuld example withstood P.C.'s scrutiny better than all other Bilmore/Mat/Tree examples.
The Ahnuld example was something that wasn't covered in my physics classes. I'm simply not qualified to comment on it, as my knowledge is limited to Newtonian physics at an introductory level. Leagl's analysis creeps into the non-Newtonian realm.*

Pretermitted(Really, all of what Leagl said just went over my head. Whoosh.)Child

* A notable example of non-Newtonian physics is quantum mechanics.

Say_hello_for_me 09-28-2003 03:52 PM

post-bilmore physics
 
Quote:

Originally posted by Greedy,Greedy,Greedy
I'm not sure I understand this. Can you lay it out in a formula?
Oh, someone here may want to shoot you for even asking. I'll do something close for gravity: (quote to follow)

"Gravitation

All bodies attract or pull upon other bodies. In other words, all matter has gravitation. One of Newton’s laws states that the force of attrac-tion between two bodies is directly proportional to the product of their masses and inversely pro-portional to the square of the distance between their two centers. Therefore, a mass has less gravitational pull on it at the top of a mountain than it has at sea level because the center is displaced farther away from the gravitational pull of the center of Earth. However, the mass remains the same even though the gravitational pull is different. Gravity also varies with latitude. It is slightly less at the equator than at the poles due to the equator’s greater distance from the center of Earth."

From http://www.tpub.com/weather2/2-6.htm

A sorta cute site for simpler explanations than I give.

Note the thing about masses and centers of mass (gravity)

As for static forces, in e.g., a wrestling mass, fughedaboudit. That stuff can be done with numbers (equal and opposite, equal and opposite...), but you'd still be ignoring dynamics, and that stuff is not understood almost at all by your reporter.

Lord give me the strength to exit this discussion now.

Hello

pretermitted_child 09-28-2003 04:00 PM

post-bilmore physics
 
Quote:

Originally posted by Say_hello_for_me

Lord give me the strength to exit this discussion now.

Hello
Sounds like someone has found a way to reconcile science and religion.

Pretermitted(atheist)Child

blueballs 09-28-2003 04:27 PM

Quote:

Originally posted by pretermitted_child
The Ahnuld example was something that wasn't covered in my physics classes. I'm simply not qualified to comment on it, as my knowledge is limited to Newtonian physics at an introductory level. Leagl's analysis creeps into the non-Newtonian realm.*

Pretermitted(Really, all of what Leagl said just went over my head. Whoosh.)Child

* A notable example of non-Newtonian physics is quantum mechanics.
You seem like a strange little boy. Are you sure you are not lobotimized_child?

Mmmm, Burger (C.J.) 09-28-2003 06:35 PM

Joe $MM
 
Just caught the ads. I guess the solution to the problem of "what stupid woman would be fooled by Fox and Joe Millionaire" now that the "secret" is out has been answered: It's only stupid American women. There are plenty of idiotic european women unfamiliar with the show for Joe $MM II.

I smell major international incident.


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