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Re: My God, you are an idiot.
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The real test is whether any of these revolutions will result in elections as W did achieve. He surely started the fire, but if Egypt or Libya or Iranistan or whereever end up something like Clinton let fester in Afghanistan it would be sad; for the people there and for us here. |
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I mean, it's great that a dictator can be removed with limited outside intervention, and certainly preferable to sending U.S. ground troops into a situation that they would be very unlikely to help. But getting rid of the bad guy is only step one. Quote:
Clinton and Somalia/Bosnia/Kosovo, with their partnership with international allies/organizations and constrained military engagement seem like closer analogs to me. [ETA: Obviously, one of those was a complete and utter fiasco and another happened appallingly late.] Or maybe you meant the Libyans (and others) would not have been inspired to revolt without the example of Iraq? |
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Interestingly, perhaps where W deserves the clearest credit is in severely weakening the Western instinct to allow fear of unsavory democratically elected regimes to result in opposition to democracy. |
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I have seen it first hand. In a previous professional incarnation, I litigated on behalf of private insureds. Hence, I still get some referrals here and there. In the past year, I've been flooded with them. Two who asked me to handle appeals have admitted they would like to continue working, but it made more sense, given their tenuous job security, to go for the guaranteed money. I'm disgusted by some of the people bringing specious claims. These couch stains seeking benefits for fibromyalgia, bipolar disorders and bad backs (best claim in the world, btw... it can never be fully verified true or false) are making it hard on lots of people with legitimate claims (MS, chemotherapy-related cognitive deficiency, etc.). |
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And isn't it proof of the Stimulus's effectiveness that, coinciding with its exhaustion, the economy started to falter? Where would it have gone if we'd never had any Stimulus? You're a Hayek fan. So am I. The problem with allowing things to collapse naturally is, What happens in the interim? We live in Mad Max Thunderdome, that's what happens. I'm a nut. I'd love to live through that kind of volatility. Problem is, my family, my parents, my friends... I don't think they'd like that. Along with 200 million or so other people in the country who would lose their fucking minds. |
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The issue isn't whether it's going up or down, it's how high it goes -- the missile is going to be slower as it closer to top of its trajectory, regardless of whether it is going up or down. With an ICBM, that point is very very high about the Earth. With a Scud, it presumably isn't, so maybe good radar plus good planes plus good missiles enables it to be shot down. |
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* I.e., Libya. |
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you seem not to be so circumspect, I mean wrt to people who you disagree with. You've never once posted a question like this to GGG whom everyone with any objectivity must admit has drifted to being a flat out troll here. Is there a method to your apparent madness? |
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One thing they all share, which Bush/Iraq did not, is that they all featured a people rising up against their leaders, instead of being invaded by a foreign government seeking to change their leaders. |
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Al J is supposed to be popular, like Fox+CNN throughout the Mid East. They cover Iraq elections while the people in all these countries suffer under dictators. It seems like a whole lot of countries stood up in the same moment. Something motivated it. |
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I get why target distance could affect maximum altitude, but it will still be above the level at which warplanes fly. |
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I have no idea if a plane could shoot one down at any particular altitude. I'm just trying to guide you and adder in your discussion by correcting corrigendum in your scientific statements. |
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Stick with what Club is saying. It's far-fetched to think that Bush's invasion of Iraq showed Libyans anything new about what was possible, but at least it doesn't undercut your point. |
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As I said, I get why target distance could affect maximum altitude, but it will still be above the level at which warplanes fly. 200 km above the planet is far, far above warplanes. Quote:
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Iraq (as would Iran) took help because the leaders were nastier and the armies stronger. Do you have an eye disease where everything looks two dimensional, and in black and white? |
Re: My God, you are an idiot.
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Assume the motion of the projective is being measured from a Free fall frame which happens to be at (x,y)=(0,0) at t=0. The equation of motion of the projectile in this frame ( by the principle of equivalence) would be y = xtan(θ). The co-ordinates of this free-fall frame, with respect to our inertial frame would be y = − gt2 / 2. That is, y = − g(x / vh)2 / 2. Now translating back to the inertial frame the co-ordinates of the projectile becomes y = xtan(θ) − g(x / vh)2 / 2 That is: y=-{g\sec^2\theta\over 2v_0^2}x^2+x\tan\theta, (where v0 is the initial velocity, θ is the angle of elevation, and g is the acceleration due to gravity). [edit] Range and height Trajectories of projectiles launched at different elevation angles but the same speed of 10 m/s in a vacuum and uniform downward gravity field of 10 m/s2. Points are at 0.05 s intervals and length of their tails is linearly proportional to their speed. t = time from launch, T = time of flight, R = range and H = highest point of trajectory (indicated with arrows). The range, R, is the greatest distance the object travels along the x-axis in the I sector. The initial velocity, vi, is the speed at which said object is launched from the point of origin. The initial angle, θi, is the angle at which said object is released. The g is the respective gravitational pull on the object within a null-medium. R={v_i^2\sin2\theta_i\over g} The height, h, is the greatest parabolic height said object reaches within its trajectory h={v_i^2\sin^2\theta_i\over 2g} [edit] Angle of elevation In terms of angle of elevation θ and initial speed v: v_h=v \cos \theta,\quad v_v=v \sin \theta \; giving the range as R= 2 v^2 \cos(\theta) \sin(\theta) / g = v^2 \sin(2\theta) / g\,. This equation can be rearranged to find the angle for a required range { \theta } = \frac 1 2 \sin^{-1} \left( { {g R} \over { v^2 } } \right) (Equation II: angle of projectile launch) Note that the sine function is such that there are two solutions for θ for a given range dh. The angle θ giving the maximum range can be found by considering the derivative or R with respect to θ and setting it to zero. {\mathrm{d}R\over \mathrm{d}\theta}={2v^2\over g} \cos(2\theta)=0 which has a non trivial solution at 2\theta=\pi/2=90^\circ, or \theta=45^\circ. The maximum range is then R_{max} = v^2/g\,. At this angle sin(π / 2) = 1, so the maximum height obtained is {v^2 \over 4g}. To find the angle giving the maximum height for a given speed calculate the derivative of the maximum height H = v2sin2(θ) / (2g) with respect to θ, that is {\mathrm{d}H\over \mathrm{d}\theta}=v^2 2\cos(\theta)\sin(\theta) /(2g) which is zero when \theta=\pi/2=90^\circ. So the maximum height H_{max}={v^2\over 2g} is obtained when the projectile is fired straight up. |
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Re: My God, you are an idiot.
If you want to give Bush some credit for what happened in Libya, I would look to the idea that we can support local combatants very effectively airpower and spotters on the ground, a la Afghanistan.
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I can see where a poly sci major might argue it coincidence, but I am a scientist, and I cannot deny that there must be some generating cause. Can you name one that makes more sense that Iraq? |
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